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-.04x^2+9.9x+5.5=0
We add all the numbers together, and all the variables
-0.04x^2+9.9x+5.5=0
a = -0.04; b = 9.9; c = +5.5;
Δ = b2-4ac
Δ = 9.92-4·(-0.04)·5.5
Δ = 98.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.9)-\sqrt{98.89}}{2*-0.04}=\frac{-9.9-\sqrt{98.89}}{-0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.9)+\sqrt{98.89}}{2*-0.04}=\frac{-9.9+\sqrt{98.89}}{-0.08} $
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